Java program to access an URL

Hi Everyone, in this blog post I will be writing a java program to access an URL. The Java program to connect to an URL is as follows:

package com.blog.techjourney;

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;

public class AccessURL {

 public static void main(String[] args) {
  String url = "http://sujithforu.blogspot.com/";
  String fakeurl = "http://thisisanincorrecttypeofurl.com/";
  System.out.println(" Connecting to existing url - "+url);
  getURLResponse(url);
  System.out.println();
  System.out.println(" Connecting to fake url - "+fakeurl);
  getURLResponse(fakeurl);
 }
 
 public static void getURLResponse(String str)
 {
  URL url;
  URLConnection urlConnection;
  HttpURLConnection httpConnection = null;
  try {
   url = new URL(str);
   urlConnection = url.openConnection();
   urlConnection.connect();
   System.out.println("Connected to "+url);
   httpConnection = (HttpURLConnection) urlConnection;
   
   int responseCode = httpConnection.getResponseCode();
   System.out.println("Response Code= " + responseCode + " for "+ url.toString());   
   httpConnection.disconnect();
   
  } catch (MalformedURLException mue) {   
   System.out.println("MalformedURLException in URLConnection ");
   httpConnection.disconnect();
  } catch(IOException ioe){
   System.out.println("IOException in URLConnection ");
   httpConnection.disconnect();
  }catch(Exception e){
   System.out.println("Exception in URLConnection ");
   httpConnection.disconnect();
  }
 }
}

The output of the program is as follows:

Connecting to existing url - http://sujithforu.blogspot.com/
Connected to http://sujithforu.blogspot.com/
Response Code= 200 for http://sujithforu.blogspot.com/
 
Connecting to fake url - http://thisisanincorrecttypeofurl.com/
IOException in URLConnection
Exception in thread "main" java.lang.NullPointerException
       at com.blog.techjourney.AccessURL.getURLResponse(AccessURL.java:42)
       at com.blog.techjourney.AccessURL.main(AccessURL.java:18)

Thank you for reading the post. Do comment below.